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1320420240231 = 31997391956239
BaseRepresentation
bin10011001101101111001…
…011011110101101100111
311200020020100122010200220
4103031233023132231213
5133113210040141411
62450332004135423
7164253146566431
oct23155713365547
94606210563626
101320420240231
11469a94890994
12193aa6097573
139769087c221
1447ca15c3651
1524531a01b06
hex1336f2deb67

1320420240231 has 16 divisors (see below), whose sum is σ = 1761922713600. Its totient is φ = 879599212128.

The previous prime is 1320420240199. The next prime is 1320420240247.

It is a happy number.

1320420240231 is nontrivially palindromic in base 10.

It is not a de Polignac number, because 1320420240231 - 25 = 1320420240199 is a prime.

It is a super-2 number, since 2×13204202402312 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1320420245231) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 23450610 + ... + 23506848.

It is an arithmetic number, because the mean of its divisors is an integer number (110120169600).

Almost surely, 21320420240231 is an apocalyptic number.

1320420240231 is a deficient number, since it is larger than the sum of its proper divisors (441502473369).

1320420240231 is a wasteful number, since it uses less digits than its factorization.

1320420240231 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 62158.

The product of its (nonzero) digits is 2304, while the sum is 24.

It can be divided in two parts, 1320420 and 240231, that added together give a palindrome (1560651).

The spelling of 1320420240231 in words is "one trillion, three hundred twenty billion, four hundred twenty million, two hundred forty thousand, two hundred thirty-one".

Divisors: 1 3 1997 3919 5991 11757 56239 168717 7826243 23478729 112309283 220400641 336927849 661201923 440140080077 1320420240231