Base | Representation |
---|---|
bin | 11000100110000100… |
… | …00100111001010011 |
3 | 1021002020001112111012 |
4 | 30103002010321103 |
5 | 204020234311311 |
6 | 10022124041135 |
7 | 645132650531 |
oct | 142302047123 |
9 | 37066045435 |
10 | 13204213331 |
11 | 5666485a01 |
12 | 26860931ab |
13 | 13257a29aa |
14 | 8d3927151 |
15 | 52433e78b |
hex | 313084e53 |
13204213331 has 2 divisors, whose sum is σ = 13204213332. Its totient is φ = 13204213330.
The previous prime is 13204213307. The next prime is 13204213333. The reversal of 13204213331 is 13331240231.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13204213331 is a prime.
It is a super-2 number, since 2×132042133312 (a number of 21 digits) contains 22 as substring.
It is a Sophie Germain prime.
Together with 13204213333, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 13204213297 and 13204213306.
It is not a weakly prime, because it can be changed into another prime (13204213333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6602106665 + 6602106666.
It is an arithmetic number, because the mean of its divisors is an integer number (6602106666).
Almost surely, 213204213331 is an apocalyptic number.
13204213331 is a deficient number, since it is larger than the sum of its proper divisors (1).
13204213331 is an equidigital number, since it uses as much as digits as its factorization.
13204213331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 13204213331 its reverse (13331240231), we get a palindrome (26535453562).
The spelling of 13204213331 in words is "thirteen billion, two hundred four million, two hundred thirteen thousand, three hundred thirty-one".
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