Base | Representation |
---|---|
bin | 1100000000100110000000… |
… | …1011001110100111111011 |
3 | 1201202022201100221200212012 |
4 | 3000021200023032213323 |
5 | 3212314443303232443 |
6 | 44025554052440135 |
7 | 2531660633553326 |
oct | 300114013164773 |
9 | 51668640850765 |
10 | 13204343024123 |
11 | 4230a26445229 |
12 | 159310b91904b |
13 | 74a2199abc44 |
14 | 339144c2d7bd |
15 | 17d71e03d118 |
hex | c02602ce9fb |
13204343024123 has 2 divisors, whose sum is σ = 13204343024124. Its totient is φ = 13204343024122.
The previous prime is 13204343024077. The next prime is 13204343024161. The reversal of 13204343024123 is 32142034340231.
It is a strong prime.
It is an emirp because it is prime and its reverse (32142034340231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13204343024123 - 224 = 13204326246907 is a prime.
It is a Sophie Germain prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13204343024123.
It is not a weakly prime, because it can be changed into another prime (13204343024183) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6602171512061 + 6602171512062.
It is an arithmetic number, because the mean of its divisors is an integer number (6602171512062).
Almost surely, 213204343024123 is an apocalyptic number.
13204343024123 is a deficient number, since it is larger than the sum of its proper divisors (1).
13204343024123 is an equidigital number, since it uses as much as digits as its factorization.
13204343024123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 41472, while the sum is 32.
Adding to 13204343024123 its reverse (32142034340231), we get a palindrome (45346377364354).
The spelling of 13204343024123 in words is "thirteen trillion, two hundred four billion, three hundred forty-three million, twenty-four thousand, one hundred twenty-three".
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