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1320440113200 = 243521353230133
BaseRepresentation
bin10011001101110000010…
…111010010100000110000
311200020021202000210021210
4103031300113102200300
5133113230132110300
62450333554120120
7164253510526215
oct23156027224060
94606252023253
101320440113200
11469aa502482a
12193ab0880040
1397694a19890
1447ca40b7b0c
152453362a050
hex133705d2830

1320440113200 has 360 divisors, whose sum is σ = 4642902317872. Its totient is φ = 318888161280.

The previous prime is 1320440113193. The next prime is 1320440113243. The reversal of 1320440113200 is 23110440231.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 43805334 + ... + 43835466.

Almost surely, 21320440113200 is an apocalyptic number.

1320440113200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1320440113200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2321451158936).

1320440113200 is an abundant number, since it is smaller than the sum of its proper divisors (3322462204672).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1320440113200 is a wasteful number, since it uses less digits than its factorization.

1320440113200 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 30273 (or 30209 counting only the distinct ones).

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 1320440113200 its reverse (23110440231), we get a palindrome (1343550553431).

The spelling of 1320440113200 in words is "one trillion, three hundred twenty billion, four hundred forty million, one hundred thirteen thousand, two hundred".