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132044231235233 is a prime number
BaseRepresentation
bin11110000001011111110001…
…011111110101011010100001
3122022112022020111201200210102
4132001133301133311122201
5114301403041144011413
61144500140555512145
736545611100413232
oct3601376137653241
9568468214650712
10132044231235233
113908970a167779
1212987081a58655
13588a943692aa5
142486d91163089
15103eb9075c458
hex7817f17f56a1

132044231235233 has 2 divisors, whose sum is σ = 132044231235234. Its totient is φ = 132044231235232.

The previous prime is 132044231235227. The next prime is 132044231235307. The reversal of 132044231235233 is 332532132440231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 99230844715024 + 32813386520209 = 9961468^2 + 5728297^2 .

It is a cyclic number.

It is not a de Polignac number, because 132044231235233 - 230 = 132043157493409 is a prime.

It is a super-3 number, since 3×1320442312352333 (a number of 43 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (132044231238233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66022115617616 + 66022115617617.

It is an arithmetic number, because the mean of its divisors is an integer number (66022115617617).

Almost surely, 2132044231235233 is an apocalyptic number.

It is an amenable number.

132044231235233 is a deficient number, since it is larger than the sum of its proper divisors (1).

132044231235233 is an equidigital number, since it uses as much as digits as its factorization.

132044231235233 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 311040, while the sum is 38.

Adding to 132044231235233 its reverse (332532132440231), we get a palindrome (464576363675464).

The spelling of 132044231235233 in words is "one hundred thirty-two trillion, forty-four billion, two hundred thirty-one million, two hundred thirty-five thousand, two hundred thirty-three".