Base | Representation |
---|---|
bin | 11110000001011111110101… |
… | …101101110100100000110001 |
3 | 122022112022102102220110002112 |
4 | 132001133311231310200301 |
5 | 114301403212303313132 |
6 | 1144500152004455105 |
7 | 36545612620115666 |
oct | 3601376555644061 |
9 | 568468372813075 |
10 | 132044302010417 |
11 | 39089746108165 |
12 | 129870a16aa495 |
13 | 588a9552433b4 |
14 | 2486d9a707a6d |
15 | 103eb96a8cab2 |
hex | 7817f5b74831 |
132044302010417 has 2 divisors, whose sum is σ = 132044302010418. Its totient is φ = 132044302010416.
The previous prime is 132044302010339. The next prime is 132044302010443. The reversal of 132044302010417 is 714010203440231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 79345355575201 + 52698946435216 = 8907601^2 + 7259404^2 .
It is a cyclic number.
It is not a de Polignac number, because 132044302010417 - 212 = 132044302006321 is a prime.
It is not a weakly prime, because it can be changed into another prime (132044302010017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66022151005208 + 66022151005209.
It is an arithmetic number, because the mean of its divisors is an integer number (66022151005209).
Almost surely, 2132044302010417 is an apocalyptic number.
It is an amenable number.
132044302010417 is a deficient number, since it is larger than the sum of its proper divisors (1).
132044302010417 is an equidigital number, since it uses as much as digits as its factorization.
132044302010417 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 16128, while the sum is 32.
Adding to 132044302010417 its reverse (714010203440231), we get a palindrome (846054505450648).
The spelling of 132044302010417 in words is "one hundred thirty-two trillion, forty-four billion, three hundred two million, ten thousand, four hundred seventeen".
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