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1320444003469 is a prime number
BaseRepresentation
bin10011001101110000100…
…110001000010010001101
311200020022000100102201211
4103031300212020102031
5133113232131102334
62450334213334421
7164253555561133
oct23156046102215
94606260312654
101320444003469
11469aa7241628
12193ab2037411
139769577c506
1447ca480b753
1524533b47a64
hex1337098848d

1320444003469 has 2 divisors, whose sum is σ = 1320444003470. Its totient is φ = 1320444003468.

The previous prime is 1320444003391. The next prime is 1320444003499. The reversal of 1320444003469 is 9643004440231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 892514772900 + 427929230569 = 944730^2 + 654163^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1320444003469 is a prime.

It is a super-2 number, since 2×13204440034692 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1320444003499) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660222001734 + 660222001735.

It is an arithmetic number, because the mean of its divisors is an integer number (660222001735).

Almost surely, 21320444003469 is an apocalyptic number.

It is an amenable number.

1320444003469 is a deficient number, since it is larger than the sum of its proper divisors (1).

1320444003469 is an equidigital number, since it uses as much as digits as its factorization.

1320444003469 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 248832, while the sum is 40.

The spelling of 1320444003469 in words is "one trillion, three hundred twenty billion, four hundred forty-four million, three thousand, four hundred sixty-nine".