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13204532550397 is a prime number
BaseRepresentation
bin1100000000100110101101…
…1110001101101011111101
31201202100012120120122000211
43000021223132031223331
53212320340313103042
644030024542552421
72531665424526136
oct300115336155375
951670176518024
1013204532550397
114231013424111
121593163298711
1374a24a039b76
14339162086c8d
1517d7309c9017
hexc026b78dafd

13204532550397 has 2 divisors, whose sum is σ = 13204532550398. Its totient is φ = 13204532550396.

The previous prime is 13204532550389. The next prime is 13204532550457. The reversal of 13204532550397 is 79305523540231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11264387212516 + 1940145337881 = 3356246^2 + 1392891^2 .

It is a cyclic number.

It is not a de Polignac number, because 13204532550397 - 23 = 13204532550389 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13204532550397.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13204532550697) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6602266275198 + 6602266275199.

It is an arithmetic number, because the mean of its divisors is an integer number (6602266275199).

Almost surely, 213204532550397 is an apocalyptic number.

It is an amenable number.

13204532550397 is a deficient number, since it is larger than the sum of its proper divisors (1).

13204532550397 is an equidigital number, since it uses as much as digits as its factorization.

13204532550397 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3402000, while the sum is 49.

The spelling of 13204532550397 in words is "thirteen trillion, two hundred four billion, five hundred thirty-two million, five hundred fifty thousand, three hundred ninety-seven".