Base | Representation |
---|---|
bin | 11110000001100001000000… |
… | …010000010000000010010001 |
3 | 122022112102122121000102221121 |
4 | 132001201000100100002101 |
5 | 114301413242423100113 |
6 | 1144500520040122241 |
7 | 36545655613410043 |
oct | 3601410020200221 |
9 | 568472577012847 |
10 | 132045552550033 |
11 | 3908a227aa3081 |
12 | 12987390466381 |
13 | 588aac4351775 |
14 | 2487078831a93 |
15 | 103ec1b75ce8d |
hex | 781840410091 |
132045552550033 has 2 divisors, whose sum is σ = 132045552550034. Its totient is φ = 132045552550032.
The previous prime is 132045552550031. The next prime is 132045552550049. The reversal of 132045552550033 is 330055255540231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 78124244019264 + 53921308530769 = 8838792^2 + 7343113^2 .
It is a cyclic number.
It is not a de Polignac number, because 132045552550033 - 21 = 132045552550031 is a prime.
Together with 132045552550031, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (132045552550031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66022776275016 + 66022776275017.
It is an arithmetic number, because the mean of its divisors is an integer number (66022776275017).
Almost surely, 2132045552550033 is an apocalyptic number.
It is an amenable number.
132045552550033 is a deficient number, since it is larger than the sum of its proper divisors (1).
132045552550033 is an equidigital number, since it uses as much as digits as its factorization.
132045552550033 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1350000, while the sum is 43.
The spelling of 132045552550033 in words is "one hundred thirty-two trillion, forty-five billion, five hundred fifty-two million, five hundred fifty thousand, thirty-three".
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