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132045552550033 is a prime number
BaseRepresentation
bin11110000001100001000000…
…010000010000000010010001
3122022112102122121000102221121
4132001201000100100002101
5114301413242423100113
61144500520040122241
736545655613410043
oct3601410020200221
9568472577012847
10132045552550033
113908a227aa3081
1212987390466381
13588aac4351775
142487078831a93
15103ec1b75ce8d
hex781840410091

132045552550033 has 2 divisors, whose sum is σ = 132045552550034. Its totient is φ = 132045552550032.

The previous prime is 132045552550031. The next prime is 132045552550049. The reversal of 132045552550033 is 330055255540231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 78124244019264 + 53921308530769 = 8838792^2 + 7343113^2 .

It is a cyclic number.

It is not a de Polignac number, because 132045552550033 - 21 = 132045552550031 is a prime.

Together with 132045552550031, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (132045552550031) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66022776275016 + 66022776275017.

It is an arithmetic number, because the mean of its divisors is an integer number (66022776275017).

Almost surely, 2132045552550033 is an apocalyptic number.

It is an amenable number.

132045552550033 is a deficient number, since it is larger than the sum of its proper divisors (1).

132045552550033 is an equidigital number, since it uses as much as digits as its factorization.

132045552550033 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1350000, while the sum is 43.

The spelling of 132045552550033 in words is "one hundred thirty-two trillion, forty-five billion, five hundred fifty-two million, five hundred fifty thousand, thirty-three".