Base | Representation |
---|---|
bin | 11110000001100101101010… |
… | …011100011001010101100111 |
3 | 122022112220120020122201102121 |
4 | 132001211222130121111213 |
5 | 114302004014132003411 |
6 | 1144503104311250411 |
7 | 36546223601432626 |
oct | 3601455234312547 |
9 | 568486506581377 |
10 | 132050555344231 |
11 | 39091364a39437 |
12 | 12988347979a07 |
13 | 588b41094b114 |
14 | 24873d101d6bd |
15 | 103ee10a67571 |
hex | 78196a719567 |
132050555344231 has 2 divisors, whose sum is σ = 132050555344232. Its totient is φ = 132050555344230.
The previous prime is 132050555344223. The next prime is 132050555344237. The reversal of 132050555344231 is 132443555050231.
It is a strong prime.
It is an emirp because it is prime and its reverse (132443555050231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 132050555344231 - 23 = 132050555344223 is a prime.
It is a super-2 number, since 2×1320505553442312 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132050555344237) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66025277672115 + 66025277672116.
It is an arithmetic number, because the mean of its divisors is an integer number (66025277672116).
Almost surely, 2132050555344231 is an apocalyptic number.
132050555344231 is a deficient number, since it is larger than the sum of its proper divisors (1).
132050555344231 is an equidigital number, since it uses as much as digits as its factorization.
132050555344231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1080000, while the sum is 43.
The spelling of 132050555344231 in words is "one hundred thirty-two trillion, fifty billion, five hundred fifty-five million, three hundred forty-four thousand, two hundred thirty-one".
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