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132052441506301 is a prime number
BaseRepresentation
bin11110000001100111011010…
…110111100010000111111101
3122022120002102200210200101001
4132001213122313202013331
5114302021400011200201
61144504015410250301
736546321413516461
oct3601473267420775
9568502380720331
10132052441506301
11390921426a2968
1212988793586991
13588b651648254
14248752d7244a1
15103eec1440301
hex7819dade21fd

132052441506301 has 2 divisors, whose sum is σ = 132052441506302. Its totient is φ = 132052441506300.

The previous prime is 132052441506281. The next prime is 132052441506383. The reversal of 132052441506301 is 103605144250231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 131957716671225 + 94724835076 = 11487285^2 + 307774^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-132052441506301 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132052441546301) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66026220753150 + 66026220753151.

It is an arithmetic number, because the mean of its divisors is an integer number (66026220753151).

Almost surely, 2132052441506301 is an apocalyptic number.

It is an amenable number.

132052441506301 is a deficient number, since it is larger than the sum of its proper divisors (1).

132052441506301 is an equidigital number, since it uses as much as digits as its factorization.

132052441506301 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 86400, while the sum is 37.

Adding to 132052441506301 its reverse (103605144250231), we get a palindrome (235657585756532).

The spelling of 132052441506301 in words is "one hundred thirty-two trillion, fifty-two billion, four hundred forty-one million, five hundred six thousand, three hundred one".