Base | Representation |
---|---|
bin | 111101011111100000… |
… | …0000000100101010001 |
3 | 110121212000220022020112 |
4 | 1322333000000211101 |
5 | 4130421142011041 |
6 | 140355312051105 |
7 | 12353256653651 |
oct | 1727700004521 |
9 | 417760808215 |
10 | 132053469521 |
11 | 51004817186 |
12 | 21714533a95 |
13 | c5b645055c |
14 | 656a0c2361 |
15 | 367d288deb |
hex | 1ebf000951 |
132053469521 has 2 divisors, whose sum is σ = 132053469522. Its totient is φ = 132053469520.
The previous prime is 132053469467. The next prime is 132053469523. The reversal of 132053469521 is 125964350231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 123977931025 + 8075538496 = 352105^2 + 89864^2 .
It is a cyclic number.
It is not a de Polignac number, because 132053469521 - 222 = 132049275217 is a prime.
Together with 132053469523, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (132053469523) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66026734760 + 66026734761.
It is an arithmetic number, because the mean of its divisors is an integer number (66026734761).
Almost surely, 2132053469521 is an apocalyptic number.
It is an amenable number.
132053469521 is a deficient number, since it is larger than the sum of its proper divisors (1).
132053469521 is an equidigital number, since it uses as much as digits as its factorization.
132053469521 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 194400, while the sum is 41.
The spelling of 132053469521 in words is "one hundred thirty-two billion, fifty-three million, four hundred sixty-nine thousand, five hundred twenty-one".
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