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132054155432501 is a prime number
BaseRepresentation
bin11110000001101001000001…
…000001101001001000110101
3122022120020212010212011010012
4132001221001001221020311
5114302033402242320001
61144504501433510005
736546412034613041
oct3601510101511065
9568506763764105
10132054155432501
1139092942107aa5
1212988b91572305
13588b86575c473
1424876531d3021
151040071b452bb
hex781a41069235

132054155432501 has 2 divisors, whose sum is σ = 132054155432502. Its totient is φ = 132054155432500.

The previous prime is 132054155432483. The next prime is 132054155432509. The reversal of 132054155432501 is 105234551450231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 87817702632100 + 44236452800401 = 9371110^2 + 6651049^2 .

It is a cyclic number.

It is not a de Polignac number, because 132054155432501 - 246 = 61685411254837 is a prime.

It is a super-2 number, since 2×1320541554325012 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132054155432509) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66027077716250 + 66027077716251.

It is an arithmetic number, because the mean of its divisors is an integer number (66027077716251).

Almost surely, 2132054155432501 is an apocalyptic number.

It is an amenable number.

132054155432501 is a deficient number, since it is larger than the sum of its proper divisors (1).

132054155432501 is an equidigital number, since it uses as much as digits as its factorization.

132054155432501 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 360000, while the sum is 41.

The spelling of 132054155432501 in words is "one hundred thirty-two trillion, fifty-four billion, one hundred fifty-five million, four hundred thirty-two thousand, five hundred one".