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13205445403517 is a prime number
BaseRepresentation
bin1100000000101010000111…
…1000011110001101111101
31201202102120012021101002122
43000022201320132031331
53212324223010403032
644030255312332325
72532030150616403
oct300124170361575
951672505241078
1013205445403517
114231441735184
121593378b440a5
1374a3641b3943
1433920b3cb473
1517d785be4012
hexc02a1e1e37d

13205445403517 has 2 divisors, whose sum is σ = 13205445403518. Its totient is φ = 13205445403516.

The previous prime is 13205445403499. The next prime is 13205445403537. The reversal of 13205445403517 is 71530454450231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9172333159396 + 4033112244121 = 3028586^2 + 2008261^2 .

It is a cyclic number.

It is not a de Polignac number, because 13205445403517 - 214 = 13205445387133 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13205445403537) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6602722701758 + 6602722701759.

It is an arithmetic number, because the mean of its divisors is an integer number (6602722701759).

Almost surely, 213205445403517 is an apocalyptic number.

It is an amenable number.

13205445403517 is a deficient number, since it is larger than the sum of its proper divisors (1).

13205445403517 is an equidigital number, since it uses as much as digits as its factorization.

13205445403517 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1008000, while the sum is 44.

Adding to 13205445403517 its reverse (71530454450231), we get a palindrome (84735899853748).

The spelling of 13205445403517 in words is "thirteen trillion, two hundred five billion, four hundred forty-five million, four hundred three thousand, five hundred seventeen".