Base | Representation |
---|---|
bin | 111101100000001001… |
… | …0010110001111100101 |
3 | 110121220112111220122122 |
4 | 1323000102112033211 |
5 | 4130442203212203 |
6 | 140401402435325 |
7 | 12353641302425 |
oct | 1730022261745 |
9 | 417815456578 |
10 | 132075054053 |
11 | 51015a19a38 |
12 | 2171b802b45 |
13 | c5baa69c77 |
14 | 656cd00485 |
15 | 36800ee538 |
hex | 1ec04963e5 |
132075054053 has 2 divisors, whose sum is σ = 132075054054. Its totient is φ = 132075054052.
The previous prime is 132075054049. The next prime is 132075054149. The reversal of 132075054053 is 350450570231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 95417356609 + 36657697444 = 308897^2 + 191462^2 .
It is a cyclic number.
It is not a de Polignac number, because 132075054053 - 22 = 132075054049 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132075054253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66037527026 + 66037527027.
It is an arithmetic number, because the mean of its divisors is an integer number (66037527027).
Almost surely, 2132075054053 is an apocalyptic number.
It is an amenable number.
132075054053 is a deficient number, since it is larger than the sum of its proper divisors (1).
132075054053 is an equidigital number, since it uses as much as digits as its factorization.
132075054053 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 63000, while the sum is 35.
The spelling of 132075054053 in words is "one hundred thirty-two billion, seventy-five million, fifty-four thousand, fifty-three".
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