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13208761596949 is a prime number
BaseRepresentation
bin1100000000110110011110…
…0010101111110000010101
31201202202010022021110021121
43000031213202233300111
53212403020432100244
644032004334043541
72532205266035002
oct300154742576025
951682108243247
1013208761596949
11423289362a406
121593b436495b1
1374a772245889
143394439c08a9
1517d8cbde4c84
hexc03678afc15

13208761596949 has 2 divisors, whose sum is σ = 13208761596950. Its totient is φ = 13208761596948.

The previous prime is 13208761596941. The next prime is 13208761597013. The reversal of 13208761596949 is 94969516780231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13031507966724 + 177253630225 = 3609918^2 + 421015^2 .

It is a cyclic number.

It is not a de Polignac number, because 13208761596949 - 23 = 13208761596941 is a prime.

It is a super-2 number, since 2×132087615969492 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13208761596941) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6604380798474 + 6604380798475.

It is an arithmetic number, because the mean of its divisors is an integer number (6604380798475).

It is a 1-persistent number, because it is pandigital, but 2⋅13208761596949 = 26417523193898 is not.

Almost surely, 213208761596949 is an apocalyptic number.

It is an amenable number.

13208761596949 is a deficient number, since it is larger than the sum of its proper divisors (1).

13208761596949 is an equidigital number, since it uses as much as digits as its factorization.

13208761596949 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 176359680, while the sum is 70.

The spelling of 13208761596949 in words is "thirteen trillion, two hundred eight billion, seven hundred sixty-one million, five hundred ninety-six thousand, nine hundred forty-nine".