Base | Representation |
---|---|
bin | 1100000000111000111100… |
… | …0111110000111011111111 |
3 | 1201202210211120201221102202 |
4 | 3000032033013300323333 |
5 | 3212410400424100133 |
6 | 44032154254142115 |
7 | 2532230611054346 |
oct | 300161707607377 |
9 | 51683746657382 |
10 | 13209425612543 |
11 | 42330a4431126 |
12 | 15940a9ab193b |
13 | 74a849996104 |
14 | 3394a7c6cb5d |
15 | 17d91a35a2e8 |
hex | c038f1f0eff |
13209425612543 has 4 divisors (see below), whose sum is σ = 13282405864728. Its totient is φ = 13136445360360.
The previous prime is 13209425612533. The next prime is 13209425612557. The reversal of 13209425612543 is 34521652490231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13209425612543 - 210 = 13209425611519 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13209425612533) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 36490125821 + ... + 36490126182.
It is an arithmetic number, because the mean of its divisors is an integer number (3320601466182).
Almost surely, 213209425612543 is an apocalyptic number.
13209425612543 is a deficient number, since it is larger than the sum of its proper divisors (72980252185).
13209425612543 is an equidigital number, since it uses as much as digits as its factorization.
13209425612543 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 72980252184.
The product of its (nonzero) digits is 1555200, while the sum is 47.
The spelling of 13209425612543 in words is "thirteen trillion, two hundred nine billion, four hundred twenty-five million, six hundred twelve thousand, five hundred forty-three".
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