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13209425612557 is a prime number
BaseRepresentation
bin1100000000111000111100…
…0111110000111100001101
31201202210211120201221110021
43000032033013300330031
53212410400424100212
644032154254142141
72532230611054366
oct300161707607415
951683746657407
1013209425612557
1142330a4431139
1215940a9ab1951
1374a849996115
143394a7c6cb6d
1517d91a35a307
hexc038f1f0f0d

13209425612557 has 2 divisors, whose sum is σ = 13209425612558. Its totient is φ = 13209425612556.

The previous prime is 13209425612533. The next prime is 13209425612587. The reversal of 13209425612557 is 75521652490231.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11896249420836 + 1313176191721 = 3449094^2 + 1145939^2 .

It is a cyclic number.

It is not a de Polignac number, because 13209425612557 - 219 = 13209425088269 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13209425612587) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6604712806278 + 6604712806279.

It is an arithmetic number, because the mean of its divisors is an integer number (6604712806279).

Almost surely, 213209425612557 is an apocalyptic number.

It is an amenable number.

13209425612557 is a deficient number, since it is larger than the sum of its proper divisors (1).

13209425612557 is an equidigital number, since it uses as much as digits as its factorization.

13209425612557 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4536000, while the sum is 52.

The spelling of 13209425612557 in words is "thirteen trillion, two hundred nine billion, four hundred twenty-five million, six hundred twelve thousand, five hundred fifty-seven".