Base | Representation |
---|---|
bin | 11110000010010011101110… |
… | …010010101011100000100111 |
3 | 122022201122012222010200000211 |
4 | 132002103232102223200213 |
5 | 114303311311034424431 |
6 | 1144541524023520251 |
7 | 36552624305351065 |
oct | 3602235622534047 |
9 | 568648188120024 |
10 | 132100012029991 |
11 | 39100333a50455 |
12 | 12995a4a8b9087 |
13 | 5892c92c7b815 |
14 | 2489963521035 |
15 | 104135788a2b1 |
hex | 7824ee4ab827 |
132100012029991 has 2 divisors, whose sum is σ = 132100012029992. Its totient is φ = 132100012029990.
The previous prime is 132100012029971. The next prime is 132100012030001. The reversal of 132100012029991 is 199920210001231.
It is a strong prime.
It is an emirp because it is prime and its reverse (199920210001231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 132100012029991 - 25 = 132100012029959 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132100012029901) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66050006014995 + 66050006014996.
It is an arithmetic number, because the mean of its divisors is an integer number (66050006014996).
Almost surely, 2132100012029991 is an apocalyptic number.
132100012029991 is a deficient number, since it is larger than the sum of its proper divisors (1).
132100012029991 is an equidigital number, since it uses as much as digits as its factorization.
132100012029991 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 17496, while the sum is 40.
The spelling of 132100012029991 in words is "one hundred thirty-two trillion, one hundred billion, twelve million, twenty-nine thousand, nine hundred ninety-one".
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