1321001440133 has 2 divisors, whose sum is σ = 1321001440134. Its totient is φ = 1321001440132.

The previous prime is 1321001440097. The next prime is 1321001440151. The reversal of 1321001440133 is 3310441001231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 893890829764 + 427110610369 = 945458^2 + 653537^2 .

It is a cyclic number.

It is not a de Polignac number, because 1321001440133 - 2¹² = 1321001436037 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1321001440099 and 1321001440108.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1321001440163) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660500720066 + 660500720067.

It is an arithmetic number, because the mean of its divisors is an integer number (660500720067).

Almost surely, 2^{1321001440133} is an apocalyptic number.

It is an amenable number.

1321001440133 is a deficient number, since it is larger than the sum of its proper divisors (1).

1321001440133 is an equidigital number, since it uses as much as digits as its factorization.

1321001440133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 1321001440133 its reverse (3310441001231), we get a palindrome (4631442441364).

The spelling of 1321001440133 in words is "one trillion, three hundred twenty-one billion, one million, four hundred forty thousand, one hundred thirty-three".