Base | Representation |
---|---|
bin | 111101100000111010… |
… | …1110000010101010001 |
3 | 110121222100112212001002 |
4 | 1323001311300111101 |
5 | 4131020341110134 |
6 | 140404133151345 |
7 | 12354405635504 |
oct | 1730165602521 |
9 | 417870485032 |
10 | 132101113169 |
11 | 510296a85a3 |
12 | 2172848b555 |
13 | c5c329226c |
14 | 657256513b |
15 | 368254a87e |
hex | 1ec1d70551 |
132101113169 has 2 divisors, whose sum is σ = 132101113170. Its totient is φ = 132101113168.
The previous prime is 132101113153. The next prime is 132101113237. The reversal of 132101113169 is 961311101231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 84364107025 + 47737006144 = 290455^2 + 218488^2 .
It is a cyclic number.
It is not a de Polignac number, because 132101113169 - 24 = 132101113153 is a prime.
It is a super-2 number, since 2×1321011131692 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (132101115169) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66050556584 + 66050556585.
It is an arithmetic number, because the mean of its divisors is an integer number (66050556585).
Almost surely, 2132101113169 is an apocalyptic number.
It is an amenable number.
132101113169 is a deficient number, since it is larger than the sum of its proper divisors (1).
132101113169 is an equidigital number, since it uses as much as digits as its factorization.
132101113169 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 29.
The spelling of 132101113169 in words is "one hundred thirty-two billion, one hundred one million, one hundred thirteen thousand, one hundred sixty-nine".
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