Base | Representation |
---|---|
bin | 1100000000111011100000… |
… | …0110101111101110100111 |
3 | 1201202212121111120120121111 |
4 | 3000032320012233232213 |
5 | 3212413302440230203 |
6 | 44032350415525451 |
7 | 2532253630415431 |
oct | 300167006575647 |
9 | 51685544516544 |
10 | 13210113211303 |
11 | 4233417580268 |
12 | 1594260229887 |
13 | 74a929282998 |
14 | 3395312d9651 |
15 | 17d95a8cd26d |
hex | c03b81afba7 |
13210113211303 has 2 divisors, whose sum is σ = 13210113211304. Its totient is φ = 13210113211302.
The previous prime is 13210113211259. The next prime is 13210113211319. The reversal of 13210113211303 is 30311231101231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13210113211303 - 217 = 13210113080231 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13210113211343) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6605056605651 + 6605056605652.
It is an arithmetic number, because the mean of its divisors is an integer number (6605056605652).
Almost surely, 213210113211303 is an apocalyptic number.
13210113211303 is a deficient number, since it is larger than the sum of its proper divisors (1).
13210113211303 is an equidigital number, since it uses as much as digits as its factorization.
13210113211303 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 324, while the sum is 22.
Adding to 13210113211303 its reverse (30311231101231), we get a palindrome (43521344312534).
The spelling of 13210113211303 in words is "thirteen trillion, two hundred ten billion, one hundred thirteen million, two hundred eleven thousand, three hundred three".
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