Base | Representation |
---|---|
bin | 111101100000111100… |
… | …1111100011011100111 |
3 | 110121222102121122101201 |
4 | 1323001321330123213 |
5 | 4131021131230203 |
6 | 140404212503331 |
7 | 12354421161166 |
oct | 1730171743347 |
9 | 417872548351 |
10 | 132102211303 |
11 | 5102a288647 |
12 | 2172891ab47 |
13 | c5c358804a |
14 | 657276d3dd |
15 | 36826b5e1d |
hex | 1ec1e7c6e7 |
132102211303 has 2 divisors, whose sum is σ = 132102211304. Its totient is φ = 132102211302.
The previous prime is 132102211289. The next prime is 132102211331. The reversal of 132102211303 is 303112201231.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132102211303 is a prime.
It is a super-2 number, since 2×1321022113032 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132102211103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66051105651 + 66051105652.
It is an arithmetic number, because the mean of its divisors is an integer number (66051105652).
Almost surely, 2132102211303 is an apocalyptic number.
132102211303 is a deficient number, since it is larger than the sum of its proper divisors (1).
132102211303 is an equidigital number, since it uses as much as digits as its factorization.
132102211303 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 132102211303 its reverse (303112201231), we get a palindrome (435214412534).
The spelling of 132102211303 in words is "one hundred thirty-two billion, one hundred two million, two hundred eleven thousand, three hundred three".
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