Base | Representation |
---|---|
bin | 11000100110110010… |
… | …01100100101001111 |
3 | 1021002122110110100010 |
4 | 30103121030211033 |
5 | 204023312233002 |
6 | 10022502004303 |
7 | 645235322511 |
oct | 142331144517 |
9 | 37078413303 |
10 | 13210274127 |
11 | 5669945526 |
12 | 2688116693 |
13 | 1326b1556b |
14 | 8d4663bb1 |
15 | 524b3a46c |
hex | 31364c94f |
13210274127 has 8 divisors (see below), whose sum is σ = 17657624880. Its totient is φ = 8784886400.
The previous prime is 13210274117. The next prime is 13210274137. The reversal of 13210274127 is 72147201231.
13210274127 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an interprime number because it is at equal distance from previous prime (13210274117) and next prime (13210274137).
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13210274127 - 28 = 13210273871 is a prime.
It is a super-2 number, since 2×132102741272 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13210274094 and 13210274103.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13210274117) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5489352 + ... + 5491757.
It is an arithmetic number, because the mean of its divisors is an integer number (2207203110).
Almost surely, 213210274127 is an apocalyptic number.
13210274127 is a deficient number, since it is larger than the sum of its proper divisors (4447350753).
13210274127 is a wasteful number, since it uses less digits than its factorization.
13210274127 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10981513.
The product of its (nonzero) digits is 4704, while the sum is 30.
Adding to 13210274127 its reverse (72147201231), we get a palindrome (85357475358).
The spelling of 13210274127 in words is "thirteen billion, two hundred ten million, two hundred seventy-four thousand, one hundred twenty-seven".
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