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132104108597 is a prime number
BaseRepresentation
bin111101100001000000…
…1001011101000110101
3110121222120012000222212
41323002001023220311
54131022122433342
6140404321303205
712354443252516
oct1730201135065
9417876160885
10132104108597
115103036405a
1221729494b05
13c5c3aa07c6
146572b04a0d
15368293d182
hex1ec204ba35

132104108597 has 2 divisors, whose sum is σ = 132104108598. Its totient is φ = 132104108596.

The previous prime is 132104108593. The next prime is 132104108611. The reversal of 132104108597 is 795801401231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 121169432836 + 10934675761 = 348094^2 + 104569^2 .

It is a cyclic number.

It is not a de Polignac number, because 132104108597 - 22 = 132104108593 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132104108593) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66052054298 + 66052054299.

It is an arithmetic number, because the mean of its divisors is an integer number (66052054299).

Almost surely, 2132104108597 is an apocalyptic number.

It is an amenable number.

132104108597 is a deficient number, since it is larger than the sum of its proper divisors (1).

132104108597 is an equidigital number, since it uses as much as digits as its factorization.

132104108597 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 60480, while the sum is 41.

The spelling of 132104108597 in words is "one hundred thirty-two billion, one hundred four million, one hundred eight thousand, five hundred ninety-seven".