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132104401241 is a prime number
BaseRepresentation
bin111101100001000001…
…0010011000101011001
3110121222120201220102112
41323002002103011121
54131022211314431
6140404331442105
712354445611641
oct1730202230531
9417876656375
10132104401241
1151030543a0a
12217295b6335
13c5c3b73a77
146572b7d521
153682999c2b
hex1ec2093159

132104401241 has 2 divisors, whose sum is σ = 132104401242. Its totient is φ = 132104401240.

The previous prime is 132104401223. The next prime is 132104401243. The reversal of 132104401241 is 142104401231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 131747946841 + 356454400 = 362971^2 + 18880^2 .

It is a cyclic number.

It is not a de Polignac number, because 132104401241 - 222 = 132100206937 is a prime.

Together with 132104401243, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (132104401243) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66052200620 + 66052200621.

It is an arithmetic number, because the mean of its divisors is an integer number (66052200621).

Almost surely, 2132104401241 is an apocalyptic number.

It is an amenable number.

132104401241 is a deficient number, since it is larger than the sum of its proper divisors (1).

132104401241 is an equidigital number, since it uses as much as digits as its factorization.

132104401241 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 132104401241 its reverse (142104401231), we get a palindrome (274208802472).

The spelling of 132104401241 in words is "one hundred thirty-two billion, one hundred four million, four hundred one thousand, two hundred forty-one".