Base | Representation |
---|---|
bin | 111101100001000001… |
… | …0010011000101011001 |
3 | 110121222120201220102112 |
4 | 1323002002103011121 |
5 | 4131022211314431 |
6 | 140404331442105 |
7 | 12354445611641 |
oct | 1730202230531 |
9 | 417876656375 |
10 | 132104401241 |
11 | 51030543a0a |
12 | 217295b6335 |
13 | c5c3b73a77 |
14 | 6572b7d521 |
15 | 3682999c2b |
hex | 1ec2093159 |
132104401241 has 2 divisors, whose sum is σ = 132104401242. Its totient is φ = 132104401240.
The previous prime is 132104401223. The next prime is 132104401243. The reversal of 132104401241 is 142104401231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 131747946841 + 356454400 = 362971^2 + 18880^2 .
It is a cyclic number.
It is not a de Polignac number, because 132104401241 - 222 = 132100206937 is a prime.
Together with 132104401243, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (132104401243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66052200620 + 66052200621.
It is an arithmetic number, because the mean of its divisors is an integer number (66052200621).
Almost surely, 2132104401241 is an apocalyptic number.
It is an amenable number.
132104401241 is a deficient number, since it is larger than the sum of its proper divisors (1).
132104401241 is an equidigital number, since it uses as much as digits as its factorization.
132104401241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 768, while the sum is 23.
Adding to 132104401241 its reverse (142104401231), we get a palindrome (274208802472).
The spelling of 132104401241 in words is "one hundred thirty-two billion, one hundred four million, four hundred one thousand, two hundred forty-one".
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