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132104414331301 is a prime number
BaseRepresentation
bin11110000010010111110100…
…101100001000000110100101
3122022202001120202211202010111
4132002113310230020012211
5114303344320032100201
61144543532524253021
736553141352322556
oct3602276454100645
9568661522752114
10132104414331301
1139102192a315a5
12129968790a1171
135893515039139
142489c6007832d
1510415140cab51
hex7825f4b081a5

132104414331301 has 2 divisors, whose sum is σ = 132104414331302. Its totient is φ = 132104414331300.

The previous prime is 132104414331247. The next prime is 132104414331311. The reversal of 132104414331301 is 103133414401231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 132084428854401 + 19985476900 = 11492799^2 + 141370^2 .

It is a cyclic number.

It is not a de Polignac number, because 132104414331301 - 29 = 132104414330789 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132104414331311) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66052207165650 + 66052207165651.

It is an arithmetic number, because the mean of its divisors is an integer number (66052207165651).

Almost surely, 2132104414331301 is an apocalyptic number.

It is an amenable number.

132104414331301 is a deficient number, since it is larger than the sum of its proper divisors (1).

132104414331301 is an equidigital number, since it uses as much as digits as its factorization.

132104414331301 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10368, while the sum is 31.

Adding to 132104414331301 its reverse (103133414401231), we get a palindrome (235237828732532).

The spelling of 132104414331301 in words is "one hundred thirty-two trillion, one hundred four billion, four hundred fourteen million, three hundred thirty-one thousand, three hundred one".