Base | Representation |
---|---|
bin | 11110000010011001100000… |
… | …011001000001111000100110 |
3 | 122022202020020200220110101102 |
4 | 132002121200121001320212 |
5 | 114303412020120430142 |
6 | 1144544432113200102 |
7 | 36553234213104266 |
oct | 3602314031017046 |
9 | 568666220813342 |
10 | 132106221264422 |
11 | 39102a2a9a1159 |
12 | 129970a2260032 |
13 | 58937424b5b32 |
14 | 2489d920377a6 |
15 | 10415bca53532 |
hex | 782660641e26 |
132106221264422 has 4 divisors (see below), whose sum is σ = 198159331896636. Its totient is φ = 66053110632210.
The previous prime is 132106221264377. The next prime is 132106221264427. The reversal of 132106221264422 is 224462122601231.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132106221264427) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33026555316104 + ... + 33026555316107.
It is an arithmetic number, because the mean of its divisors is an integer number (49539832974159).
Almost surely, 2132106221264422 is an apocalyptic number.
132106221264422 is a deficient number, since it is larger than the sum of its proper divisors (66053110632214).
132106221264422 is an equidigital number, since it uses as much as digits as its factorization.
132106221264422 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 66053110632213.
The product of its (nonzero) digits is 110592, while the sum is 38.
Adding to 132106221264422 its reverse (224462122601231), we get a palindrome (356568343865653).
The spelling of 132106221264422 in words is "one hundred thirty-two trillion, one hundred six billion, two hundred twenty-one million, two hundred sixty-four thousand, four hundred twenty-two".
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