Base | Representation |
---|---|
bin | 11000100110110111… |
… | …11000010010011001 |
3 | 1021002200210012002111 |
4 | 30103123320102121 |
5 | 204024002234213 |
6 | 10022525032321 |
7 | 645244312123 |
oct | 142333702231 |
9 | 37080705074 |
10 | 13210977433 |
11 | 566a285975 |
12 | 26883b56a1 |
13 | 1327000714 |
14 | 8d47a8213 |
15 | 524c28a3d |
hex | 3136f8499 |
13210977433 has 2 divisors, whose sum is σ = 13210977434. Its totient is φ = 13210977432.
The previous prime is 13210977431. The next prime is 13210977529. The reversal of 13210977433 is 33477901231.
13210977433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 13198103689 + 12873744 = 114883^2 + 3588^2 .
It is a cyclic number.
It is not a de Polignac number, because 13210977433 - 21 = 13210977431 is a prime.
Together with 13210977431, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (13210977431) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6605488716 + 6605488717.
It is an arithmetic number, because the mean of its divisors is an integer number (6605488717).
Almost surely, 213210977433 is an apocalyptic number.
It is an amenable number.
13210977433 is a deficient number, since it is larger than the sum of its proper divisors (1).
13210977433 is an equidigital number, since it uses as much as digits as its factorization.
13210977433 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 95256, while the sum is 40.
The spelling of 13210977433 in words is "thirteen billion, two hundred ten million, nine hundred seventy-seven thousand, four hundred thirty-three".
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