Base | Representation |
---|---|
bin | 11110000010011101000010… |
… | …001110101111111010011011 |
3 | 122022202121000202111100120102 |
4 | 132002131002032233322123 |
5 | 114303442300104021222 |
6 | 1144550300103450015 |
7 | 36553430131514456 |
oct | 3602350216577233 |
9 | 568677022440512 |
10 | 132110010220187 |
11 | 391045a473975a |
12 | 1299797b15690b |
13 | 5893bc74842ac |
14 | 248a23133249d |
15 | 10417404dbd92 |
hex | 7827423afe9b |
132110010220187 has 2 divisors, whose sum is σ = 132110010220188. Its totient is φ = 132110010220186.
The previous prime is 132110010220091. The next prime is 132110010220211. The reversal of 132110010220187 is 781022010011231.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132110010220187 - 240 = 131010498592411 is a prime.
It is not a weakly prime, because it can be changed into another prime (132110010222187) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66055005110093 + 66055005110094.
It is an arithmetic number, because the mean of its divisors is an integer number (66055005110094).
Almost surely, 2132110010220187 is an apocalyptic number.
132110010220187 is a deficient number, since it is larger than the sum of its proper divisors (1).
132110010220187 is an equidigital number, since it uses as much as digits as its factorization.
132110010220187 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1344, while the sum is 29.
The spelling of 132110010220187 in words is "one hundred thirty-two trillion, one hundred ten billion, ten million, two hundred twenty thousand, one hundred eighty-seven".
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