132110011081 has 2 divisors, whose sum is σ = 132110011082. Its totient is φ = 132110011080.

The previous prime is 132110011079. The next prime is 132110011151. The reversal of 132110011081 is 180110011231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 126943276681 + 5166734400 = 356291^2 + 71880^2 .

It is a cyclic number.

It is not a de Polignac number, because 132110011081 - 2¹ = 132110011079 is a prime.

It is a super-3 number, since 3×132110011081³ (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 132110011079, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (132110011681) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66055005540 + 66055005541.

It is an arithmetic number, because the mean of its divisors is an integer number (66055005541).

Almost surely, 2^132110011081 is an apocalyptic number.

It is an amenable number.

132110011081 is a deficient number, since it is larger than the sum of its proper divisors (1).

132110011081 is an equidigital number, since it uses as much as digits as its factorization.

132110011081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 19.

The spelling of 132110011081 in words is "one hundred thirty-two billion, one hundred ten million, eleven thousand, eighty-one".