Base | Representation |
---|---|
bin | 111101100001001011… |
… | …1111011111100100010 |
3 | 110121222222102002111011 |
4 | 1323002113323330202 |
5 | 4131030134324014 |
6 | 140405053211134 |
7 | 12354545045350 |
oct | 1730227737442 |
9 | 417888362434 |
10 | 132110073634 |
11 | 51033768740 |
12 | 2172b490aaa |
13 | c5c50ab906 |
14 | 65738187d0 |
15 | 368321a7c4 |
hex | 1ec25fbf22 |
132110073634 has 128 divisors (see below), whose sum is σ = 265028101632. Its totient is φ = 47811133440.
The previous prime is 132110073607. The next prime is 132110073637. The reversal of 132110073634 is 436370011231.
It is a junction number, because it is equal to n+sod(n) for n = 132110073596 and 132110073605.
It is not an unprimeable number, because it can be changed into a prime (132110073637) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 170905272 + ... + 170906044.
It is an arithmetic number, because the mean of its divisors is an integer number (2070532044).
Almost surely, 2132110073634 is an apocalyptic number.
132110073634 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
132110073634 is an abundant number, since it is smaller than the sum of its proper divisors (132918027998).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132110073634 is a wasteful number, since it uses less digits than its factorization.
132110073634 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1580.
The product of its (nonzero) digits is 9072, while the sum is 31.
Adding to 132110073634 its reverse (436370011231), we get a palindrome (568480084865).
The spelling of 132110073634 in words is "one hundred thirty-two billion, one hundred ten million, seventy-three thousand, six hundred thirty-four".
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