Base | Representation |
---|---|
bin | 11110000010011101001010… |
… | …001001011001001110001011 |
3 | 122022202121101000102000012211 |
4 | 132002131022021121032023 |
5 | 114303443033104044001 |
6 | 1144550321210245551 |
7 | 36553433333435464 |
oct | 3602351211311613 |
9 | 568677330360184 |
10 | 132110143034251 |
11 | 39104662702948 |
12 | 129979b77268b7 |
13 | 5893c18b468b5 |
14 | 248a244c25d6b |
15 | 104174bec4351 |
hex | 78274a25938b |
132110143034251 has 2 divisors, whose sum is σ = 132110143034252. Its totient is φ = 132110143034250.
The previous prime is 132110143034203. The next prime is 132110143034263. The reversal of 132110143034251 is 152430341011231.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132110143034251 - 219 = 132110142509963 is a prime.
It is not a weakly prime, because it can be changed into another prime (132110143034351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66055071517125 + 66055071517126.
It is an arithmetic number, because the mean of its divisors is an integer number (66055071517126).
Almost surely, 2132110143034251 is an apocalyptic number.
132110143034251 is a deficient number, since it is larger than the sum of its proper divisors (1).
132110143034251 is an equidigital number, since it uses as much as digits as its factorization.
132110143034251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8640, while the sum is 31.
Adding to 132110143034251 its reverse (152430341011231), we get a palindrome (284540484045482).
The spelling of 132110143034251 in words is "one hundred thirty-two trillion, one hundred ten billion, one hundred forty-three million, thirty-four thousand, two hundred fifty-one".
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