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132110331233 is a prime number
BaseRepresentation
bin111101100001001100…
…0111010110101100001
3110121222222220011211212
41323002120322311201
54131030221044413
6140405102515505
712354550200356
oct1730230726541
9417888804755
10132110331233
1151033924231
122172b595b95
13c5c516bc3a
14657388462d
15368326bca8
hex1ec263ad61

132110331233 has 2 divisors, whose sum is σ = 132110331234. Its totient is φ = 132110331232.

The previous prime is 132110331229. The next prime is 132110331253. The reversal of 132110331233 is 332133011231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 117287755729 + 14822575504 = 342473^2 + 121748^2 .

It is a cyclic number.

It is not a de Polignac number, because 132110331233 - 22 = 132110331229 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 132110331199 and 132110331208.

It is not a weakly prime, because it can be changed into another prime (132110331253) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66055165616 + 66055165617.

It is an arithmetic number, because the mean of its divisors is an integer number (66055165617).

Almost surely, 2132110331233 is an apocalyptic number.

It is an amenable number.

132110331233 is a deficient number, since it is larger than the sum of its proper divisors (1).

132110331233 is an equidigital number, since it uses as much as digits as its factorization.

132110331233 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 972, while the sum is 23.

Adding to 132110331233 its reverse (332133011231), we get a palindrome (464243342464).

The spelling of 132110331233 in words is "one hundred thirty-two billion, one hundred ten million, three hundred thirty-one thousand, two hundred thirty-three".