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13211033323 is a prime number
BaseRepresentation
bin11000100110111000…
…00101111011101011
31021002200220000202111
430103130011323223
5204024011031243
610022530143151
7645244634065
oct142334057353
937080800674
1013211033323
11566a313964
122688421ab7
13132701cca7
148d47c0735
15524c3a39d
hex313705eeb

13211033323 has 2 divisors, whose sum is σ = 13211033324. Its totient is φ = 13211033322.

The previous prime is 13211033293. The next prime is 13211033327. The reversal of 13211033323 is 32333011231.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13211033323 - 29 = 13211032811 is a prime.

It is a super-4 number, since 4×132110333234 (a number of 42 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 13211033294 and 13211033303.

It is not a weakly prime, because it can be changed into another prime (13211033327) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6605516661 + 6605516662.

It is an arithmetic number, because the mean of its divisors is an integer number (6605516662).

Almost surely, 213211033323 is an apocalyptic number.

13211033323 is a deficient number, since it is larger than the sum of its proper divisors (1).

13211033323 is an equidigital number, since it uses as much as digits as its factorization.

13211033323 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 972, while the sum is 22.

Adding to 13211033323 its reverse (32333011231), we get a palindrome (45544044554).

The spelling of 13211033323 in words is "thirteen billion, two hundred eleven million, thirty-three thousand, three hundred twenty-three".