132110354041 has 2 divisors, whose sum is σ = 132110354042. Its totient is φ = 132110354040.

The previous prime is 132110354009. The next prime is 132110354071. The reversal of 132110354041 is 140453011231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 126796527225 + 5313826816 = 356085^2 + 72896^2 .

It is a cyclic number.

It is not a de Polignac number, because 132110354041 - 2⁵ = 132110354009 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 132110353997 and 132110354015.

It is not a weakly prime, because it can be changed into another prime (132110354071) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66055177020 + 66055177021.

It is an arithmetic number, because the mean of its divisors is an integer number (66055177021).

Almost surely, 2^132110354041 is an apocalyptic number.

It is an amenable number.

132110354041 is a deficient number, since it is larger than the sum of its proper divisors (1).

132110354041 is an equidigital number, since it uses as much as digits as its factorization.

132110354041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 132110354041 its reverse (140453011231), we get a palindrome (272563365272).

The spelling of 132110354041 in words is "one hundred thirty-two billion, one hundred ten million, three hundred fifty-four thousand, forty-one".