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132110403111241 is a prime number
BaseRepresentation
bin11110000010011101011001…
…101001100000100101001001
3122022202122001010210021202221
4132002131121221200211021
5114303444101144024431
61144550403100454041
736553442642160442
oct3602353151404511
9568678033707687
10132110403111241
1139104786499605
1212997a6a84a321
135893c5a9a6bc9
14248a26b5a62c9
151041764c49111
hex782759a60949

132110403111241 has 2 divisors, whose sum is σ = 132110403111242. Its totient is φ = 132110403111240.

The previous prime is 132110403111229. The next prime is 132110403111277. The reversal of 132110403111241 is 142111304011231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 129316811780025 + 2793591331216 = 11371755^2 + 1671404^2 .

It is a cyclic number.

It is not a de Polignac number, because 132110403111241 - 25 = 132110403111209 is a prime.

It is a super-2 number, since 2×1321104031112412 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (132110403121241) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66055201555620 + 66055201555621.

It is an arithmetic number, because the mean of its divisors is an integer number (66055201555621).

Almost surely, 2132110403111241 is an apocalyptic number.

It is an amenable number.

132110403111241 is a deficient number, since it is larger than the sum of its proper divisors (1).

132110403111241 is an equidigital number, since it uses as much as digits as its factorization.

132110403111241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576, while the sum is 25.

Adding to 132110403111241 its reverse (142111304011231), we get a palindrome (274221707122472).

The spelling of 132110403111241 in words is "one hundred thirty-two trillion, one hundred ten billion, four hundred three million, one hundred eleven thousand, two hundred forty-one".