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132110422130020 = 22537329873541201
BaseRepresentation
bin11110000010011101011010…
…110010000011110101100100
3122022202122002110120112122011
4132002131122302003311210
5114303444121031130040
61144550405020244004
736553443262631665
oct3602353262036544
9568678073515564
10132110422130020
11391047961a9704
1212997a750a0604
135893c61905819
14248a26dd1736c
1510417667543ea
hex78275ac83d64

132110422130020 has 48 divisors (see below), whose sum is σ = 284931435802608. Its totient is φ = 51415697203200.

The previous prime is 132110422129999. The next prime is 132110422130041. The reversal of 132110422130020 is 20031224011231.

It is an interprime number because it is at equal distance from previous prime (132110422129999) and next prime (132110422130041).

It can be written as a sum of positive squares in 8 ways, for example, as 3719292196 + 132106702837824 = 60986^2 + 11493768^2 .

It is a junction number, because it is equal to n+sod(n) for n = 132110422129973 and 132110422130000.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 243835420 + ... + 244376620.

It is an arithmetic number, because the mean of its divisors is an integer number (5936071579221).

Almost surely, 2132110422130020 is an apocalyptic number.

132110422130020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

132110422130020 is an abundant number, since it is smaller than the sum of its proper divisors (152821013672588).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

132110422130020 is a wasteful number, since it uses less digits than its factorization.

132110422130020 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 871120 (or 871118 counting only the distinct ones).

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 132110422130020 its reverse (20031224011231), we get a palindrome (152141646141251).

The spelling of 132110422130020 in words is "one hundred thirty-two trillion, one hundred ten billion, four hundred twenty-two million, one hundred thirty thousand, twenty".

Divisors: 1 2 4 5 10 20 37 74 148 185 370 740 329873 541201 659746 1082402 1319492 1649365 2164804 2706005 3298730 5412010 6597460 10824020 12205301 20024437 24410602 40048874 48821204 61026505 80097748 100122185 122053010 200244370 244106020 400488740 178527597473 357055194946 714110389892 892637987365 1785275974730 3570551949460 6605521106501 13211042213002 26422084426004 33027605532505 66055211065010 132110422130020