Base | Representation |
---|---|
bin | 11110000010011101100000… |
… | …111100100011001101110111 |
3 | 122022202122100200011110222011 |
4 | 132002131200330203031313 |
5 | 114303444324014341122 |
6 | 1144550423152545051 |
7 | 36553445656631254 |
oct | 3602354074431567 |
9 | 568678320143864 |
10 | 132110525543287 |
11 | 39104839611615 |
12 | 12997aa3852187 |
13 | 5893c7a172ac5 |
14 | 248a27d95642b |
15 | 1041770880377 |
hex | 782760f23377 |
132110525543287 has 2 divisors, whose sum is σ = 132110525543288. Its totient is φ = 132110525543286.
The previous prime is 132110525543273. The next prime is 132110525543387. The reversal of 132110525543287 is 782345525011231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132110525543287 - 243 = 123314432521079 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 132110525543287.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132110525543387) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66055262771643 + 66055262771644.
It is an arithmetic number, because the mean of its divisors is an integer number (66055262771644).
Almost surely, 2132110525543287 is an apocalyptic number.
132110525543287 is a deficient number, since it is larger than the sum of its proper divisors (1).
132110525543287 is an equidigital number, since it uses as much as digits as its factorization.
132110525543287 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2016000, while the sum is 49.
The spelling of 132110525543287 in words is "one hundred thirty-two trillion, one hundred ten billion, five hundred twenty-five million, five hundred forty-three thousand, two hundred eighty-seven".
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