Base | Representation |
---|---|
bin | 11000100110111000… |
… | …10110001101111111 |
3 | 1021002201000102021011 |
4 | 30103130112031333 |
5 | 204024020200111 |
6 | 10022531420051 |
7 | 645245332423 |
oct | 142334261577 |
9 | 37081012234 |
10 | 13211100031 |
11 | 566a359a98 |
12 | 2688454627 |
13 | 132704446c |
14 | 8d47dab83 |
15 | 524c50021 |
hex | 31371637f |
13211100031 has 2 divisors, whose sum is σ = 13211100032. Its totient is φ = 13211100030.
The previous prime is 13211099989. The next prime is 13211100041. The reversal of 13211100031 is 13000111231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13211100031 - 215 = 13211067263 is a prime.
It is a super-2 number, since 2×132111000312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13211099984 and 13211100020.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13211100041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6605550015 + 6605550016.
It is an arithmetic number, because the mean of its divisors is an integer number (6605550016).
Almost surely, 213211100031 is an apocalyptic number.
13211100031 is a deficient number, since it is larger than the sum of its proper divisors (1).
13211100031 is an equidigital number, since it uses as much as digits as its factorization.
13211100031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18, while the sum is 13.
Adding to 13211100031 its reverse (13000111231), we get a palindrome (26211211262).
The spelling of 13211100031 in words is "thirteen billion, two hundred eleven million, one hundred thousand, thirty-one".
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