Base | Representation |
---|---|
bin | 10011001110011000010… |
… | …011001010011001001100 |
3 | 11200022000102202122211220 |
4 | 103032120103022121030 |
5 | 133121113142320022 |
6 | 2450524250443340 |
7 | 164306224510644 |
oct | 23163023123114 |
9 | 4608012678756 |
10 | 1321110120012 |
11 | 46a309248871 |
12 | 194059133550 |
13 | 97770787107 |
14 | 47d29085524 |
15 | 2457237585c |
hex | 133984ca64c |
1321110120012 has 12 divisors (see below), whose sum is σ = 3082590280056. Its totient is φ = 440370040000.
The previous prime is 1321110120007. The next prime is 1321110120047. The reversal of 1321110120012 is 2100210111231.
It is a tau number, because it is divible by the number of its divisors (12).
It is a junction number, because it is equal to n+sod(n) for n = 1321110119973 and 1321110120000.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 55046254989 + ... + 55046255012.
It is an arithmetic number, because the mean of its divisors is an integer number (256882523338).
Almost surely, 21321110120012 is an apocalyptic number.
1321110120012 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
1321110120012 is an abundant number, since it is smaller than the sum of its proper divisors (1761480160044).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1321110120012 is a wasteful number, since it uses less digits than its factorization.
1321110120012 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 110092510008 (or 110092510006 counting only the distinct ones).
The product of its (nonzero) digits is 24, while the sum is 15.
Adding to 1321110120012 its reverse (2100210111231), we get a palindrome (3421320231243).
The spelling of 1321110120012 in words is "one trillion, three hundred twenty-one billion, one hundred ten million, one hundred twenty thousand, twelve".
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