Base | Representation |
---|---|
bin | 11000100110111000… |
… | …11111100100011111 |
3 | 1021002201002100210211 |
4 | 30103130133210133 |
5 | 204024022411320 |
6 | 10022532313251 |
7 | 645245552203 |
oct | 142334374437 |
9 | 37081070724 |
10 | 13211138335 |
11 | 566a38584a |
12 | 2688472827 |
13 | 1327058a25 |
14 | 8d480ab03 |
15 | 524c5b55a |
hex | 31371f91f |
13211138335 has 8 divisors (see below), whose sum is σ = 15856901280. Its totient is φ = 10566553824.
The previous prime is 13211138329. The next prime is 13211138359. The reversal of 13211138335 is 53383111231.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13211138335 - 213 = 13211130143 is a prime.
It is a super-2 number, since 2×132111383352 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13211138297 and 13211138306.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 269752 + ... + 314941.
It is an arithmetic number, because the mean of its divisors is an integer number (1982112660).
Almost surely, 213211138335 is an apocalyptic number.
13211138335 is a deficient number, since it is larger than the sum of its proper divisors (2645762945).
13211138335 is an equidigital number, since it uses as much as digits as its factorization.
13211138335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 589217.
The product of its digits is 6480, while the sum is 31.
Adding to 13211138335 its reverse (53383111231), we get a palindrome (66594249566).
The spelling of 13211138335 in words is "thirteen billion, two hundred eleven million, one hundred thirty-eight thousand, three hundred thirty-five".
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