Base | Representation |
---|---|
bin | 11110000010011111000100… |
… | …110000011111100011001101 |
3 | 122022202210200101010222121112 |
4 | 132002133010300133203031 |
5 | 114304011241211313031 |
6 | 1144551301252341405 |
7 | 36553535322312005 |
oct | 3602370460374315 |
9 | 568683611128545 |
10 | 132112200104141 |
11 | 39105518889a04 |
12 | 12998290614865 |
13 | 589418608330a |
14 | 248a39c0d9005 |
15 | 104181c8ab62b |
hex | 7827c4c1f8cd |
132112200104141 has 2 divisors, whose sum is σ = 132112200104142. Its totient is φ = 132112200104140.
The previous prime is 132112200104033. The next prime is 132112200104201. The reversal of 132112200104141 is 141401002211231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 129594408674116 + 2517791430025 = 11383954^2 + 1586755^2 .
It is a cyclic number.
It is not a de Polignac number, because 132112200104141 - 218 = 132112199841997 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132112200134141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66056100052070 + 66056100052071.
It is an arithmetic number, because the mean of its divisors is an integer number (66056100052071).
Almost surely, 2132112200104141 is an apocalyptic number.
It is an amenable number.
132112200104141 is a deficient number, since it is larger than the sum of its proper divisors (1).
132112200104141 is an equidigital number, since it uses as much as digits as its factorization.
132112200104141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 384, while the sum is 23.
Adding to 132112200104141 its reverse (141401002211231), we get a palindrome (273513202315372).
The spelling of 132112200104141 in words is "one hundred thirty-two trillion, one hundred twelve billion, two hundred million, one hundred four thousand, one hundred forty-one".
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