Base | Representation |
---|---|
bin | 111101100001010000… |
… | …0001010111100101001 |
3 | 110122000010110202112021 |
4 | 1323002200022330221 |
5 | 4131031212412413 |
6 | 140405211344441 |
7 | 12354602305552 |
oct | 1730240127451 |
9 | 418003422467 |
10 | 132112232233 |
11 | 51034a02503 |
12 | 21730152121 |
13 | c5c56862a7 |
14 | 6573c1b329 |
15 | 36834e518d |
hex | 1ec280af29 |
132112232233 has 2 divisors, whose sum is σ = 132112232234. Its totient is φ = 132112232232.
The previous prime is 132112232221. The next prime is 132112232257. The reversal of 132112232233 is 332232211231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 71774696464 + 60337535769 = 267908^2 + 245637^2 .
It is an emirp because it is prime and its reverse (332232211231) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132112232233 is a prime.
It is a super-3 number, since 3×1321122322333 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 132112232198 and 132112232207.
It is not a weakly prime, because it can be changed into another prime (132112232633) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66056116116 + 66056116117.
It is an arithmetic number, because the mean of its divisors is an integer number (66056116117).
Almost surely, 2132112232233 is an apocalyptic number.
It is an amenable number.
132112232233 is a deficient number, since it is larger than the sum of its proper divisors (1).
132112232233 is an equidigital number, since it uses as much as digits as its factorization.
132112232233 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2592, while the sum is 25.
Adding to 132112232233 its reverse (332232211231), we get a palindrome (464344443464).
The spelling of 132112232233 in words is "one hundred thirty-two billion, one hundred twelve million, two hundred thirty-two thousand, two hundred thirty-three".
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