Base | Representation |
---|---|
bin | 1100000000111111101010… |
… | …1010111100110001111111 |
3 | 1201202222111100000020020102 |
4 | 3000033322222330301333 |
5 | 3212423044334420312 |
6 | 44033053312311315 |
7 | 2532323411066063 |
oct | 300177252746177 |
9 | 51688440006212 |
10 | 13211229998207 |
11 | 423393aa1084a |
12 | 159451224253b |
13 | 74aa76760437 |
14 | 3395d9767aa3 |
15 | 17d9c397cec2 |
hex | c03faabcc7f |
13211229998207 has 2 divisors, whose sum is σ = 13211229998208. Its totient is φ = 13211229998206.
The previous prime is 13211229998147. The next prime is 13211229998231. The reversal of 13211229998207 is 70289992211231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13211229998207 - 210 = 13211229997183 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13211829998207) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6605614999103 + 6605614999104.
It is an arithmetic number, because the mean of its divisors is an integer number (6605614999104).
Almost surely, 213211229998207 is an apocalyptic number.
13211229998207 is a deficient number, since it is larger than the sum of its proper divisors (1).
13211229998207 is an equidigital number, since it uses as much as digits as its factorization.
13211229998207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1959552, while the sum is 56.
The spelling of 13211229998207 in words is "thirteen trillion, two hundred eleven billion, two hundred twenty-nine million, nine hundred ninety-eight thousand, two hundred seven".
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