Base | Representation |
---|---|
bin | 111101100001010001… |
… | …1000110101100000110 |
3 | 110122000011220211101100 |
4 | 1323002203012230012 |
5 | 4131031412014342 |
6 | 140405240040530 |
7 | 12354611660526 |
oct | 1730243065406 |
9 | 418004824340 |
10 | 132113001222 |
11 | 51035388234 |
12 | 21730463146 |
13 | c5c5895307 |
14 | 6573d7b686 |
15 | 36835e7e4c |
hex | 1ec28c6b06 |
132113001222 has 24 divisors (see below), whose sum is σ = 288920025576. Its totient is φ = 43626099456.
The previous prime is 132113001173. The next prime is 132113001233. The reversal of 132113001222 is 222100311231.
132113001222 is a `hidden beast` number, since 132 + 11 + 300 + 1 + 222 = 666.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a junction number, because it is equal to n+sod(n) for n = 132113001195 and 132113001204.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 34295323 + ... + 34299174.
It is an arithmetic number, because the mean of its divisors is an integer number (12038334399).
Almost surely, 2132113001222 is an apocalyptic number.
132113001222 is an abundant number, since it is smaller than the sum of its proper divisors (156807024354).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132113001222 is a wasteful number, since it uses less digits than its factorization.
132113001222 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 68594612 (or 68594609 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 18.
Adding to 132113001222 its reverse (222100311231), we get a palindrome (354213312453).
The spelling of 132113001222 in words is "one hundred thirty-two billion, one hundred thirteen million, one thousand, two hundred twenty-two".
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