Base | Representation |
---|---|
bin | 10011001110011001011… |
… | …111011011100011011011 |
3 | 11200022001211101102101221 |
4 | 103032121133123203123 |
5 | 133121133302110433 |
6 | 2450530243152511 |
7 | 164306556451153 |
oct | 23163137334333 |
9 | 4608054342357 |
10 | 1321130113243 |
11 | 46a319563aa6 |
12 | 194063975737 |
13 | 97774967425 |
14 | 47d2b9ab763 |
15 | 24573ec472d |
hex | 133997db8db |
1321130113243 has 2 divisors, whose sum is σ = 1321130113244. Its totient is φ = 1321130113242.
The previous prime is 1321130113187. The next prime is 1321130113267. The reversal of 1321130113243 is 3423110311231.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1321130113243 is a prime.
It is a super-2 number, since 2×13211301132432 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1321130113643) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660565056621 + 660565056622.
It is an arithmetic number, because the mean of its divisors is an integer number (660565056622).
Almost surely, 21321130113243 is an apocalyptic number.
1321130113243 is a deficient number, since it is larger than the sum of its proper divisors (1).
1321130113243 is an equidigital number, since it uses as much as digits as its factorization.
1321130113243 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 1321130113243 its reverse (3423110311231), we get a palindrome (4744240424474).
The spelling of 1321130113243 in words is "one trillion, three hundred twenty-one billion, one hundred thirty million, one hundred thirteen thousand, two hundred forty-three".
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