Base | Representation |
---|---|
bin | 11110000010011111110101… |
… | …110100010110110000110110 |
3 | 122022202212210201221121021211 |
4 | 132002133311310112300312 |
5 | 114304014432414402220 |
6 | 1144551515054232034 |
7 | 36553564605441205 |
oct | 3602376564266066 |
9 | 568685721847254 |
10 | 132113023200310 |
11 | 39105900465279 |
12 | 129984801b561a |
13 | 5894287761979 |
14 | 248a43955723c |
15 | 1041869c96b5a |
hex | 7827f5d16c36 |
132113023200310 has 16 divisors (see below), whose sum is σ = 248142721837536. Its totient is φ = 50547591485248.
The previous prime is 132113023200307. The next prime is 132113023200311. The reversal of 132113023200310 is 13002320311231.
It is a super-2 number, since 2×1321130232003102 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132113023200311) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 287202224119 + ... + 287202224578.
It is an arithmetic number, because the mean of its divisors is an integer number (15508920114846).
Almost surely, 2132113023200310 is an apocalyptic number.
132113023200310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
132113023200310 is a deficient number, since it is larger than the sum of its proper divisors (116029698637226).
132113023200310 is a wasteful number, since it uses less digits than its factorization.
132113023200310 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 574404448727.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 132113023200310 its reverse (13002320311231), we get a palindrome (145115343511541).
The spelling of 132113023200310 in words is "one hundred thirty-two trillion, one hundred thirteen billion, twenty-three million, two hundred thousand, three hundred ten".
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