13211304023 has 2 divisors, whose sum is σ = 13211304024. Its totient is φ = 13211304022.

The previous prime is 13211303951. The next prime is 13211304031. The reversal of 13211304023 is 32040311231.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13211304023 - 2⁸ = 13211303767 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13211303986 and 13211304004.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13211304053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6605652011 + 6605652012.

It is an arithmetic number, because the mean of its divisors is an integer number (6605652012).

Almost surely, 2^13211304023 is an apocalyptic number.

13211304023 is a deficient number, since it is larger than the sum of its proper divisors (1).

13211304023 is an equidigital number, since it uses as much as digits as its factorization.

13211304023 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 13211304023 its reverse (32040311231), we get a palindrome (45251615254).

The spelling of 13211304023 in words is "thirteen billion, two hundred eleven million, three hundred four thousand, twenty-three".