Base | Representation |
---|---|
bin | 11000100110111010… |
… | …01010001111001100 |
3 | 1021002201102020112121 |
4 | 30103131022033030 |
5 | 204024044004400 |
6 | 10022540142324 |
7 | 645250210546 |
oct | 142335121714 |
9 | 37081366477 |
10 | 13211313100 |
11 | 566a495087 |
12 | 26885379a4 |
13 | 13270ba43b |
14 | 8d4854696 |
15 | 524c9321a |
hex | 31374a3cc |
13211313100 has 36 divisors (see below), whose sum is σ = 28673805384. Its totient is φ = 5283556480.
The previous prime is 13211313079. The next prime is 13211313107. The reversal of 13211313100 is 131311231.
13211313100 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×132113131002 (a number of 21 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (13211313107) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 821739 + ... + 837661.
It is an arithmetic number, because the mean of its divisors is an integer number (796494594).
Almost surely, 213211313100 is an apocalyptic number.
13211313100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13211313100 is an abundant number, since it is smaller than the sum of its proper divisors (15462492284).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13211313100 is a wasteful number, since it uses less digits than its factorization.
13211313100 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 24234 (or 24227 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 13211313100 its reverse (131311231), we get a palindrome (13342624331).
It can be divided in two parts, 1321131 and 3100, that added together give a palindrome (1324231).
The spelling of 13211313100 in words is "thirteen billion, two hundred eleven million, three hundred thirteen thousand, one hundred".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.066 sec. • engine limits •